在C#中可能用到,获取Json中很多的键值,如果一个一个手敲出来有些麻烦,不过本方法还是会损耗一些性能滴。懒人编程找方法…
using Newtonsoft.Json.Linq;


//单层Json
string json = "{\"name\":\"tom\",\"nickname\":\"tony\",\"sex\":\"male\",\"age\":20,\"email\":\"123@123.com\"}";
var o = JObject.Parse(json);
foreach (var item in o.Children())
{
    var p = item as JProperty;
    string s = p.Name + ":" + p.Value;
}


//多层Json
var o = JObject.Parse(yourJsonString);  
  
foreach (JToken child in o.Children())  
{  
    //var property1 = child as JProperty;  
    //MessageBox.Show(property1.Name + ":" + property1.Value);  
    foreach (JToken grandChild in child)  
    {  
        foreach (JToken grandGrandChild in grandChild)  
        {  
            var property = grandGrandChild as JProperty;  
            if (property != null)  
            {  
                MessageBox.Show(property.Name + ":" + property.Value);  
            }  
        }  
    }  
}

 

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